Algebra Word Problems — Coins
Practice algebraic word problems with two coin types. Enter the total number of coins and the total dollar amount — the calculator solves the system and shows full step-by-step work so you can learn.
Solution
Enter inputs and click Solve & Show Work.
How it works (brief)
Let x = number of Coin A. Then Coin B count = (TotalCoins − x). Convert the total amount to cents. Solve: (valueA * x) + (valueB * (Total − x)) = totalCents. Algebraically: x = (totalCents − valueB * Total) / (valueA − valueB). The calculator shows full algebraic steps and highlights when integer counts are not whole (no valid whole-number solution).
Let x = number of Coin A. Then Coin B count = (TotalCoins − x). Convert the total amount to cents. Solve: (valueA * x) + (valueB * (Total − x)) = totalCents. Algebraically: x = (totalCents − valueB * Total) / (valueA − valueB). The calculator shows full algebraic steps and highlights when integer counts are not whole (no valid whole-number solution).